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Reversing Numbers
Number, Level 2 Problem Take any 2-digit number. Reverse the digits to make another 2-digit number. Add the two numbers together. How many answers do you get which are still 2-digit numbers? What do the answers have in common? What is this problem about? This problem practices the addition of 2-digit numbers. As the curriculum document states that children need to develop "accuracy, efficiency, and confidence in calculating mentally, on paper, and with a calculator" this problem can be used to practice any or all of these skills. Encourage the children to share the methods that they use to solve the problem. For example some children may mentally count on while others will find it easier to use a rounding method. 91 + 19 counting on: 91 + 10 + 9 rounding: 91 + 20 1 This problem also offers the opportunity for children to "play" with numbers. As well as practising addition the children are encouraged to look for patterns in their answers. This play encourages children to increase their understanding of numbers and how they relate to one another. It also helps develop problem solving skill and creativity. Achievement Objectives - write and solve story problems which involve whole numbers using addition, subtraction, multiplication or division Mathematical Processes Resources required calculator (depending on addition method being practised) hundred's board Blackline master of the problem (English) Blackline master of the problem (Maaori) Specific learning outcomes The children will be able to: - add 2-digit numbers with and without renaming Teaching Sequence
Extension problem Is there a pattern in the numbers that give 3-digit sums? Solution There are many patterns that can be found in this problem. Let's try a few numbers and see what we get: 13 + 31 = 44 26 + 62 = 88 47 + 74 = 121 54 + 45 = 99 68 + 86 = 154 Now we can see that if the sum of the digits in the 2-digit number is less than 10 then the sum of the reversed numbers is less than 100. 27 + 72 = 99 The sum of the digits in the 2-digit number determines the sum of the reversed numbers in the following way: If the sum is 6 the answer is 66 (24 + 42 = 66; 15 + 51 = 66 etc) If the sum is 8 then the sum of the reversed numbers is 88. For the development band students, you might notice that the sum in every case above is a multiple of 11. Extension: Once again the 3-digit sums are all multiples of 11. To see this notive that 68 + 86 gives the same answer as 66 + 88. Now both 66 and 88 are multiples of 11, so the sum is too. |
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