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Pauls Patterns Algebra, Level 4 Problem If Pauls pattern was: What is this problem about? The aim here is to get control over terms in a sequence. In this context that means to be able to state a rule for any term in the sequence. What we are aiming to do here is to get an expression for the nth term of a sequence. In Algebra Level 3 there are some other problems like this that can now be tackled from a more sophisticated point of view (see Toothpick Squares and Race To 100). Achievement Objectives Algebra (Level 4) - find a rule to describe any member of a number sequence and express it in words. Mathematical Processes Resources Blackline master of the problem (English) Blackline master of the problem (Maaori) Specific learning outcomes The children will be able to: - use their own words to describe a number sequence - use a rule to find a member of a number sequence Teaching sequence As the lists develop the children attempt to guess the rule however they keep this rule secret until the end of the game when rules are shared. For example: The rule is multiples of 4 Do belong 12, 24, 8, 4 Do not belong 1, 0, 5, 7, 6, 13, 15 Solution to the problem In Pauls sequence, the first term is 3. To get from the first to the second term, he had to add 4. The same thing has to be done in going from the second term to the third term. And if he adds another 4 he gets the fourth term. So to tell Pesi how to generate the pattern, he only has to say "Pesi, you just start at 3 and keep adding 4. That way youll get all members of my pattern." Now that doesnt help us with the 50th term. Of course, Pesi could now do the adding 4 until he got to the 50th term but can he do better than that? Well, to get the first term Paul took 3 and added no 4s. To get the second term, Paul took 3 and added one 4. To get the third term he took 3 and added two 4s. To get the fourth term he took 3 and added three 4s. The number of 4s that Paul adds is always one less than the number of the term. So for the sixth term Paul will take 3 and add five 4s. So Paul can now tell Pesi how to get the 50th term quickly. "Pesi, you just take 3 and add 49 4s." To which Pesi replies "Great, so the 50th term is 3 + 49 x 4 = 199. Thanks, I needed that." Then now its Pesis turn. Remember his sequence is 3, 6, 12, 24, So here he is starting with 3 and doubling each time to get the next number in the sequence. So he says just that. "Paul, just take 3 and keep doubling." Well maybe thats not too accurate but it will do for now. Since the doubling is done one less time than the number of the term in the sequence, he tells Paul, "Take 3 and double it, then double it again and keep doing this for 49 doublings. So the 50th term is 3 x 2 x 2 x x 2, where there are 49 2s." You might need the computer to work that one out. The number 3 x 249 is very big! Its roughly 3 with 15 zeros after it! |
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